If y changes at a rate proportional to y, then y must be of the form y(t) = Ce^{kt}, with k and C constant. Is the statement true or false?
I think the statement would be false because the growth is proportional so e is not used. But I am not sure if I am right. Thanks for any help.True and False Question about calculus?
It should be true. The statement that y changes at a rate proportional to y can be written as y' is proportional to y
and we make it an equation by using constant of proportionality k, that is y' = ky.
Of course y'= dy/dt so dy/dt = ky.
That is a differential equation which can be solved by
separation of variables. Multiply both sides by 1/y to obtain
1/y (dy/dt) = k
now multiply both sides by dt to effect the separation of variables so we obtain
[1/y]dy = k dt
NEXT integrate both sides with respect to their variable of integration
⌠[1/y]dy = ⌠ k dt
which gives us
ln y + c = kt
Since c is an arbitrary constant, we may name it as Ln C1
since that can be an arbitrary constant too.
now
ln y + ln C1 = ln (C1)y = kt
consequently (C1)y = e^(kt)
so y = [1/C1]e^(kt)
note, however that we may , since C is arbitrary, we may simply make this C=1/C1
so y = C e^(kt)
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment